Problems on Ages - Practice Test 01

Practice Test: Question Set - 01


1. A father's age is three times the sum of the ages of his two children, but 20 years hence his age will be equal to sum of their ages. Then the father’s age is
    (A) 30 years
    (B) 40 years
    (C) 35 years
    (D) 45 years

2. The ratio of Present ages of two brothers is 1:2 and 5 years back, the ratio was 1:3. What will be the ratio of their ages after 5 years?
    (A) 1:4
    (B) 2:3
    (C) 3:5
    (D) 5:6

3. The ratio of the father's age to the son's age is 4:1. The product of their ages is 196. The ratio of their ages after 5 years will be:
    (A) 3: 1
    (B) 10:3
    (C) 11:4
    (D) 14:5

4. The ratio between the school ages of ‘A’ and ‘B’ is 5:6 respectively. If the ratio between the one-third age of ‘A’ and half of B’s age is 5:9, then what is the school age of ‘B’?
    (A) 25 years
    (B) 30 years
    (C) 36 years
    (D) Can’t be determined

5. In 10 years, ‘A’ will be twice as old as ‘B’ was 10 years ago. If ‘A’ is now 9 years older than ‘B’, find the present age of ‘B’.
    (A) 3 9
    (B) 2 7
    (C) 45
    (D) 26

6. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is:
    (A) 14 years
    (B) 18 years
    (C) 20 years
    (D) 22 years

7. ‘A’ is as much younger than ‘B’ as he is older than ‘C’. If the sum of B's and C's ages is 40 years, find the age of ‘A’.
    (A) 40 years
    (B) 10 years
    (C) 25 years
    (D) 20 years

8. ‘A’ got married 8 years ago. His present age is 6/5 times his age at the time of his marriage. A’s sister was 10 years younger to him at the time of his marriage. The age of A’s sister is:
    (A) 32 years
    (B) 36 years
    (C) 38 years
    (D) 40 years

9. Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as his son. The sum of the present ages of the son and the father is:
    (A) 54
    (B) 72
    (C) 105
    (D) 108

10. The ages of ‘R’ and ‘S’ differs by 16 years. Six years ago, S's age was thrice as that of R's. Then R's present age is
    (A) 15 years
    (B) 20 years
    (C) 14 years
    (D) 30 years

11. A’s grandfather was 8 times older to him 16 years ago. He would be 3 times of his age 8 years from now. Eight years ago, what was the ratio of A’s age to that of his grandfather?
    (A) 1:2
    (B) 1:5
    (C) 3:8
    (D) None of these

12. A father is 4 times as old as his son; in 20 years he will be only twice as old as his son. Then the respective ages of father and son are
    (A) 40, 10 years
    (B) 80, 20 years
    (C) 60, 15 years
    (D) 48, 12 years

13. The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:
    (A) 12 years
    (B) 14 years
    (C) 18 years
    (D) 20 years

14. The difference between the ages of two persons is 8 years. 15 years ago, the elder one was twice as old as the younger one. Then the present age of the elder person is
    (A) 23 years
    (B) 31 years
    (C) 34 years
    (D) 40 years

15. ‘Q’ is much younger than ‘R’ as he is older than ‘T’. If the sum of the ages of ‘R’ and ‘T’ is 50 years, what is definitely the difference between ‘R’ and Q’s age?
    (A) 1 year
    (B) 2 years
    (C) 25 years
    (D) Data inadequate

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Problems on Ages:
Formula:                Problems on Ages Formulas
Solved Examples:  Solved Examples: Set 01     Solved Examples: Set 02
Practice Test:         Practice Test: 01     Practice Test: 02
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