## Trains Aptitude Questions and Answers with Detailed Solution:

__Question No. 01__**A 300 meter long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?**

(A) 320 m

(B) 350 m

(C) 650 m

(D) None of
these

Answer:
Option B

__Explanation:__
Speed =
(300/18) m/sec = (50/3) m/sec.

Let the
length of the platform be

*x*meters.
Then, [(

*x*+ 300)/39] = 50/3
=> 3(

*x*+ 300) = 1950
=>

*x*= 350 m.

__Question No. 02__**A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?**

(A) 120 m

(B) 240 m

(C) 300 m

(D) 120 m

Answer:
Option B

__Explanation:__
Speed = [54
× (5/18)] m/sec = 15 m/sec

Length of
the train = (15 × 20) m = 300 m.

Let the
length of the platform be

*x*meters.
Then, (

*x*+ 300)/36 = 15
=>

*x*+ 300 = 540
=>

*x*= 240 m.

__Question No. 03__**A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?**

(A) 230 m

(B) 240 m

(C) 260 m

(D) 270 m

Answer:
Option D

__Explanation:__
Speed = [72×
(5/18)] m/sec = 20 m/sec

Time = 26
sec.

Let the
length of the train be

*x*meters.
Then, (

*x*+ 250)/26 = 20
=>

*x*+ 250 = 520
=>

*x*= 270

__Question No. 04__**A train 800 meters long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:**

(A) 130 m

(B) 360 m

(C) 500 m

(D) 540 m

Answer:
Option C

__Explanation:__
Speed = [78
× (5/18)] m/sec = (65/3) m/sec

Time = 1
minute = 60 seconds.

Let the
length of the tunnel be

*x*meters.
Then, [(800
+

*x*)/60] = 65/3
=> 3(800 +

*x*) = 3900
=>

*x*= 500.

__Question No. 05__**A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:**

(A) 50 m

(B) 150 m

(C) 200 m

(D) None of
these

Answer:
Option B

__Explanation:__
Let the
length of the train be

*x*meters and its speed by*y*m/sec.
Then,

*x*/*y*= 15
=>

*y*=*x*/15
∴ [(

*x*+ 100)/25] =*x*/15
=> 15(

*x*+ 100) = 25*x*
=> 15

*x*+ 1500 = 25*x*
=> 1500 = 10

*x*
=>

*x*= 150 m.

__Question No. 06__**A train overtakes two persons walking along a railway track. The first one walks at 4.5 km/hr. The other one walks at 5.4 km/hr. The train needs 8.4 and 8.5 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?**

(A) 66 km/hr

(B) 72 km/hr

(C) 78 km/hr

(D) 81 km/hr

Answer:
Option D

__Explanation:__
4.5 km/hr =
[4.5 × (5/18)] m/sec = (5/4) m/sec = 1.25 m/sec, and

5.4 km/hr =
[5.4 × (5/18)] m/sec = (3/2) m/sec = 1.5 m/sec

Let the
speed of the train be

*x*m/sec.
Then, (

*x*- 1.25) x 8.4 = (*x*- 1.5) x 8.5
=> 8.4

*x*- 10.5 = 8.5*x*- 12.75
=> 0.1

*x*= 2.25
=>

*x*= 22.5
∴ Speed
of the train = [2.25 × (18/5)] km/hr = 81 km/hr

__Question No. 07__**A 270 meters long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?**

(A) 230 m

(B) 240 m

(C) 250 m

(D) None of
these

Answer:
Option A

__Explanation:__
Relative
speed = (120 + 80) km/hr = [200 × (5/18)] m/sec = (500/9) m/sec

Let the length
of the other train be

*x*meters.
Then, (

*x*+ 270)/9 = 500/9
=>

*x*+ 270 = 500
=>

*x*= 230

__Question No. 08__**A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:**

(A) 45 km/hr

(B) 50 km/hr

(C) 54 km/hr

(D) 55 km/hr

Answer:
Option B

__Explanation:__
Speed of the
train relative to man = (125/10) m/sec

= (25/2)
m/sec

= [(25/2) ×
(18/5)] km/hr

= 45 km/hr.

Let the
speed of the train be

*x*km/hr. Then, relative speed = (*x*- 5) km/hr.
∴

*x*- 5 = 45
=>

*x*= 50 km/hr.

__Question No. 09__**Two trains are running in opposite directions with the same speed. If the length of each train is 120 meters and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:**

(A) 10

(B) 18

(C) 36

(D) 72

Answer:
Option C

__Explanation:__
Let the speed of each
train be

*x*m/sec.
Then, relative speed of
the two trains = 2

*x*m/sec.
So, 2

*x*= (120 + 120)/12
=> 2

*x*= 20
=>

*x*= 10
∴ Speed of each train = 10 m/sec = [10 × (18/5)]
km/hr = 36 km/hr.

__Question No. 10__**Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:**

(A) 1 : 3

(B) 3 : 2

(C) 3 : 4

(D) None of
these

Answer:
Option B

__Explanation:__
Let the
speeds of the two trains be

*x*m/sec and y m/sec respectively.
Then, length
of the first train = 27

*x*meters,
And length
of the second train = 17

*y*meters.
∴ (27

*x*+ 17*y*)/(*x*+*y*) = 23
=> 27

*x*+ 17*y*= 23*x*+ 23*y*
=> 4

*x*= 6*y*
=>

*x*/*y*= 3/2

__Trains Aptitude:__**Formula: Trains Aptitude Formulas**

**Solved Examples: Solved Examples: Set 01 Solved Examples: Set 02**

**Practice Test: Practice Test: 01 Practice Test: 02**

## Post a Comment Blogger Facebook