Percentage Important Aptitude Formulas:
(I). Concept
of Percentage:
1. By a certain percent, we mean that
many hundredths. Thus x percent means x hundredths, written as x%.
To express x% as a fraction: We
have, x% = x/100.
Thus, 20% =20/100 =1/5;
48% =48/100 =12/25, etc.
2.
Percentage increase = (increase/original) × 100
3.
Percentage decrease = (decrease/original) × 100
4. Increased
value at rate of x% after time‘t’ be
Increased value = Present
value × [(100 + x)/100]t
Decreased value = Present
value × [(100 - x)/100]t
5. Initial
value that is increased to present value at the rate of x% in time t, then
Initial value = present value ×
[100/(100 + x)]t
6. Initial
value that is decreased to present value at the rate of x% in time t, then
Initial value = present value ×
[100/(100 - x)]t
(II) Results on Population:
Let the
population of the town be P now and suppose it increases at the rate of R% per
annum, then:
1. Population after n years = P × [1 + (R/100)]n
2. Population n years ago = P/[1 + (R/100)]n
(III).
Results on Depreciation:
Let the
present value of a machine be P. Suppose it depreciates at the rate R% per
annum. Then,
1. Value of the machine after n years = P
× [1 - (R/100)]n
2. Value of the machine n years ago = P/[1
- (R/100)]n
(IV). If
A is R% more than B, then B is less than A by [(R/(100 + R)) × 100]%.
If A is R% less than B, then B is more
than A by [(R/(100 - R)) × 100]%.
Example: 01
If the
sales tax reduced from 3½ % to 3⅓ %, then what difference does it make
to a person who purchases an article with market price of Rs. 8400?
Solution:
Required difference = [3½ % of Rs.8400] –
[3⅓ % of Rs.8400]
= [(7/2) - (10/3)]
% of Rs.8400 =1/6 % of Rs.8400
= Rs. [(1/6)
× 8400] × (1/100) = Rs. 14.
Example: 02
A man calculates that if he lets his house
for Rs 80 per month, he would earn 7½ % p.a on his outlay after allowing for repairs.
Actually he is able to let it for Rs. 76 p.m and had to spend Rs. 60 more on
repairs. He thus gets only 6% p.a on his outlay. Find the outlay?
Solution: Let, price of
the outlay is x.
Therefore, 1½ % of x = (4 × 12) + 60
or, (3/2) × (x/100) = 108
or, x = 7200or, (3/2) × (x/100) = 108
Percentage Aptitude:
Formula: Percentage Aptitude Formulas
Solved Examples: Solved Examples: Set 01
Practice Test: Practice Test: 01 Practice Test: 02
Formula: Percentage Aptitude Formulas
Solved Examples: Solved Examples: Set 01
Practice Test: Practice Test: 01 Practice Test: 02
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